Class 4 Olympiad

Class 4 Maths Olympiad Practice Test – 35 Questions, 60 Minutes, No Negative Marking

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Class 4 Maths Olympiad Practice Test — 35 Questions, 60 Minutes, No Negative Marking

Class 4 · Mathematics · full paper format · free, no sign-up

Math Olympiad › Class 4 › Problems

A full Class 4 maths Olympiad paper built to the same shape as the real thing:
35 questions in 60 minutes, split into three sections of 5, 10 and 20 questions, and
no negative marking — a wrong answer costs you nothing. This is also called Grade 4 in
many schools.

All 35 questions are original and every answer is worked out in full. Start the timer, attempt
the whole paper, then press Submit and read where the marks actually went.

Questions
35
Time
60 min
Negative marking
None
Cost
Free
There is no negative marking in this paper. Marks are only ever added. Attempt
every one of the 35 questions, because an unanswered question scores 0 while a wrong one still scores 0
— guessing can only ever help you.
Section I is 5 questions, Section II is 10, Section III is 20.
That 5 / 10 / 20 split is the real paper’s structure. Section III is worth two thirds of the paper,
so do not spend all your time on the first fifteen questions.
Time left
60:00

Section I · 5 questions

The first five questions. These are the warm-up part of the paper.

Q1ThinkNumber patterns

A staircase is built with blocks. The top row has 1 block, the next row has 3, then 5, then 7. Each new row has 2 more blocks than the row above. How many blocks are in the sixth row?




Correct answer: (b) 11

  1. Row 1 has 1 block, row 2 has 3, row 3 has 5, row 4 has 7. The step is always 2.

  2. Row 5 has 9 blocks and row 6 has 11 blocks.

  3. So the sixth row holds 11 blocks.

Usual mistake: Starting an arithmetic pattern from zero instead of from the first given term.

Why the other options look tempting

  • (a) Starts the pattern at 0 blocks and then adds 2 each time, as if the top row were empty.
  • (c) Keeps adding 2 but counts one row too many, reaching 12 instead of 11.
  • (d) Carries on adding 2 and then adds a 3 as well, double-counting the last step.
Q2ThinkFractions and decimals

A ribbon 1 metre long is cut into 4 equal pieces. One of those pieces is cut in half again. What fraction of the original ribbon is the smallest piece now?




Correct answer: (d) 1/8

  1. Cutting into 4 equal pieces makes each piece 1/4 of the whole ribbon.

  2. Cutting one of those pieces in half makes the new piece 1/2 of 1/4.

  3. Half of a quarter is 1/8 of the original ribbon.

Usual mistake: Stopping after the first cut, or halving 1/4 by 4 instead of by 2.

Why the other options look tempting

  • (a) Answers after the first cut only, and forgets that one piece was halved again.
  • (b) Cuts the piece into 4 rather than 2, which would give 1/16 of the whole.
  • (c) Reports the size of one of the pieces that were not cut again, which is still 1/2.
Q3ThinkOdd and even

Two different odd numbers are added together and the sum is written on the board. Then one of the two original numbers is added to that sum. What must be true about the number now on the board?




Correct answer: (d) odd

  1. Adding two odd numbers always gives an even number.

  2. The number added next is one of the original odd numbers.

  3. An even number plus an odd number is always odd.

Usual mistake: Stopping after the first step, or inventing a divisibility rule from the number of terms.

Why the other options look tempting

  • (a) Works out the first step correctly, then forgets to do the second addition.
  • (b) Thinks that adding three numbers always gives a multiple of 3, which depends on the digits and not on the count.
  • (c) Assumes an even number plus an odd number must be a multiple of 6, which is not a rule of parity.
Q4ThinkMoney

A shopkeeper buys 12 identical notebooks for Rs.180. He then sells 8 of those notebooks for Rs.160. What is his profit on the 8 notebooks he sold?




Correct answer: (b) ₹40

  1. Cost of 1 notebook is 180 divided by 12, which is Rs.15.

  2. So the cost of the 8 notebooks sold is 8 times 15, which is Rs.120.

  3. Profit is what he received minus what those 8 notebooks cost: 160 − 120 = Rs.40.

Usual mistake: Using the cost of the whole lot against the sale of only part of it.

Why the other options look tempting

  • (a) Subtracts the Rs.160 earned on 8 notebooks from the Rs.180 spent on all 12, mixing the two lots.
  • (c) Adds the Rs.120 cost to the Rs.160 received instead of taking one from the other.
  • (d) Works out the cost of one notebook as Rs.15 and the money received per notebook as Rs.20, then subtracts in the wrong order.
Q5ThinkMeasurement

A ribbon is 2 metres 40 centimetres long. A piece 75 centimetres long is cut off. How long is the ribbon that is left?




Correct answer: (a) 165 cm

  1. 1 metre is 100 centimetres, so 2 m 40 cm is 240 cm.

  2. Cutting 75 cm off leaves 240 − 75 centimetres.

  3. What remains is 165 cm long.

Usual mistake: Converting units once and then borrowing, which changes the arithmetic without being noticed.

Why the other options look tempting

  • (b) Borrows 1 metre without adjusting, leaving 30 cm − 75 cm and then adding 125 to make it look sensible.
  • (c) Adds the length that was cut off to the total instead of removing it.
  • (d) Subtracts 105 cm, which is the 75 cm cut plus the extra 30 cm that should have been borrowed from the metres.

Section II · 10 questions

The next ten questions. This is where the main thinking happens.

Q6ChallengeNumber patterns

Triangles are laid out in rows so that the first row has 1 triangle, the second has 3, the third has 6 and the fourth has 10. If the same pattern continues, how many triangles are there in the eighth row altogether?




Correct answer: (c) 36

  1. Row n holds 1 + 2 + … + n triangles, which is n multiplied by n + 1, halved.

  2. For the eighth row that is 8 times 9, halved.

  3. 8 times 9 is 72, and 72 halved is 36 triangles.

Usual mistake: Carrying the same step forward instead of letting it increase by 1 each time.

Why the other options look tempting

  • (a) Keeps adding 5, which was the last step used, instead of letting the step grow.
  • (b) Adds 5, 6, 7, 8 and 9 to the fourth row, which overshoots the eighth row.
  • (d) Uses n times n instead of n times n + 1, halved, so the answer is 8 points too small.
Q7ChallengeFractions and decimals

Ravi had Rs.60. He spent 1/3 of it on a book, and then spent 1/4 of what was left on a notebook. How much money does he have now?




Correct answer: (c) ₹30

  1. 1/3 of Rs.60 is Rs.20, so Rs.40 is left after the book.

  2. 1/4 of the Rs.40 that is left is Rs.10, spent on the notebook.

  3. So Ravi has 40 − 10 = Rs.30 left.

Usual mistake: Applying the second fraction to the starting amount instead of the amount remaining.

Why the other options look tempting

  • (a) Takes 1/4 of the original Rs.60, which is Rs.15, instead of 1/4 of the Rs.40 that remained.
  • (b) Reports the amount spent on the book rather than the amount left at the end.
  • (d) Stops after the first purchase and reports Rs.40, ignoring the notebook.
Q8ChallengeFactors and multiples

A number leaves no remainder when it is divided by 6, by 9, or by 15. What is the smallest such number that is greater than 100?




Correct answer: (c) 180

  1. 6, 9 and 15 are made from the prime factors 2, 3 and 5, and 9 needs 3 twice.

  2. Their least common multiple is 2 times 9 times 5, which is 90.

  3. 90 is not greater than 100, so the next multiple of 90 is 180.

Usual mistake: Giving the least common multiple when a larger one is asked for, or checking only some of the divisors.

Why the other options look tempting

  • (a) Gives the least common multiple itself, but the question asks for a number greater than 100.
  • (b) Skips a multiple: 90 times 3 is the second one above 100, not the first.
  • (d) Picks 6 times 20, which is divisible by 6 and by 15 but leaves remainder 3 when divided by 9.
Q9ChallengeGeometry and symmetry

A square of side 2 cm is cut into 4 equal smaller squares, and then one diagonal is drawn in each of the 4 small squares. How many triangles are there in total?




Correct answer: (a) 8

  1. One diagonal cuts a square into exactly 2 triangles.

  2. There are 4 small squares, and each gives 2 triangles.

  3. So there are 4 times 2 = 8 triangles altogether.

Usual mistake: Forgetting that a single diagonal produces two triangles, not one.

Why the other options look tempting

  • (b) Counts one triangle per small square instead of the two that a diagonal makes.
  • (c) Counts the 8 small triangles and then adds 4 more that are not actually formed.
  • (d) Treats a square as having four halves along diagonals, when it has only two.
Q10ChallengeTime and speed

A train leaves at 9:15 in the morning and arrives at 11:40 the same morning. It stands still at one station for 20 minutes on the way. For how many minutes was the train actually moving?




Correct answer: (c) 125 minutes

  1. From 9:15 to 11:40 is 2 hours 25 minutes, which is 145 minutes.

  2. The train was not moving for 20 of those minutes.

  3. So the moving time is 145 − 20 = 125 minutes.

Usual mistake: Reading a journey time as moving time when a stoppage is mentioned.

Why the other options look tempting

  • (a) Gives the total time from departure to arrival and forgets the stop.
  • (b) Takes the stop off twice, or removes 40 minutes instead of 20.
  • (d) Adds the stop to the travelling time instead of removing it.
Q11ChallengeRemainders

A number leaves remainder 3 when it is divided by 7, and it also leaves remainder 3 when it is divided by 5. What is the smallest such number that is greater than 40?




Correct answer: (c) 73

  1. Subtracting 3 from the number leaves something divisible by both 7 and 5.

  2. A number divisible by both 7 and 5 is a multiple of 35.

  3. So the number is 3 more than a multiple of 35. The values are 38 and 73, and 38 is too small.

  4. So the smallest such number above 40 is 73.

Usual mistake: Finding the smallest match and stopping, without checking that it is above the stated limit.

Why the other options look tempting

  • (a) This is the smallest such number, but it is not greater than 40.
  • (b) 63 is a multiple of 7, so dividing it by 7 leaves remainder 0 and not 3.
  • (d) 75 is a multiple of 5, so dividing it by 5 leaves remainder 0 and not 3.
Q12ChallengeWorking backwards

A number is multiplied by 4, then 7 is subtracted, and the result is 29. What was the number to start with?




Correct answer: (d) 9

  1. Work backwards from 29. The last thing done was subtracting 7, so add 7: 29 + 7 = 36.

  2. Before that the number was multiplied by 4, so divide by 4: 36 divided by 4 is 9.

  3. So the number was 9.

Usual mistake: Reversing a subtraction as a subtraction instead of an addition.

Why the other options look tempting

  • (a) Reverses one step too many and divides by 4 a second time.
  • (b) Stops after multiplying back and forgets to undo the subtraction of 7.
  • (c) Subtracts 7 from the result while working backwards, when the step was to add 7.
Q13ChallengeArithmetic operations

The average of four numbers is 15. Three of the numbers are 12, 18 and 20. What is the fourth number?




Correct answer: (d) 10

  1. An average of 15 across 4 numbers means the four numbers add up to 4 times 15, which is 60.

  2. The three known numbers add up to 12 + 18 + 20, which is 50.

  3. The fourth number is 60 − 50 = 10.

Usual mistake: Thinking the average is another value in the list rather than a balance of the total.

Why the other options look tempting

  • (a) Subtracts only 12 and 18 from the total of 60.
  • (b) Assumes the missing number is also the average, which is not what an average means.
  • (c) Reports the largest of the three given numbers.
Q14ChallengeNumber puzzles

How many different four-digit numbers can be made using the digits 1, 2, 3 and 4, when each digit must be used exactly once?




Correct answer: (a) 24

  1. The first place can take any of the 4 digits, the second place then has 3 choices, the third has 2, and the last has 1.

  2. So the total is 4 times 3 times 2 times 1.

  3. That gives 24 different numbers.

Usual mistake: Keeping some digits fixed in a set position instead of letting every digit move.

Why the other options look tempting

  • (b) Only swaps digits within two fixed pairs, so it counts 2 times 2 times 3 ways.
  • (c) Gives 4 choices in each of the 4 places, forgetting that a digit cannot be reused.
  • (d) Counts the arrangements of 5 digits instead of 4.
Q15ChallengeLogical reasoning

Some cats are black. All cats are animals. Which of these statements must be true?




Correct answer: (a) All cats are animals.

  1. The first statement tells us that at least some cats are black, which says nothing about the rest.

  2. The second statement says that every cat is an animal, without exception.

  3. So all cats are animals must be true.

Usual mistake: Turning a statement about some members into a statement about all members.

Why the other options look tempting

  • (b) Reverses the second statement. We know every cat is an animal, not that every animal is a cat.
  • (c) Overreaches from some cats being black to all black things being cats.
  • (d) May be true or false, and the two statements do not settle it either way.

Section III · 20 questions

The last twenty questions. This is the part that decides a place on the board.

Q16OlympiadLogical reasoning

Five children stand in a row. Meena is second from the left and Reena is second from the right. How many children stand between Meena and Reena?




Correct answer: (b) 1

  1. Number the places 1 to 5 from the left. Second from the left is place 2 and second from the right is place 4.

  2. Only place 3 lies between place 2 and place 4.

  3. So 1 child stands between them.

Usual mistake: Counting positions moved rather than positions in between.

Why the other options look tempting

  • (a) Counts the number of steps from Meena to Reena instead of the children strictly between them.
  • (c) Places the two children next to each other, which would need them to be in the same place.
  • (d) Counts the children between the two ends of the row rather than between the two named children.
Q17OlympiadRemainders

Find the smallest two-digit number which leaves remainder 1 when divided by 4, remainder 2 when divided by 5, and remainder 3 when divided by 6.




Correct answer: (a) 57

  1. Each remainder is 1 less than the divisor, so adding 3 to the number makes it divisible by 4, by 5 and by 6.

  2. The least common multiple of 4, 5 and 6 is 60, so the number is 60 − 3, which is 57.

  3. Checking: 57 = 4 times 14 + 1, 57 = 5 times 11 + 2, and 57 = 6 times 9 + 3, so all three conditions hold.

  4. So the number is 57.

Usual mistake: Not checking a candidate against every one of the conditions it has to satisfy.

Why the other options look tempting

  • (b) 57 works, but 53 leaves remainder 3 when divided by 5 rather than remainder 2.
  • (c) 61 leaves remainder 1 when divided by 5 rather than remainder 2.
  • (d) 43 leaves remainder 3 when divided by 4 rather than remainder 1.
Q18OlympiadNumber patterns

A pattern begins 1, 4, 9, 16, 25, 36. The numbers are the squares of whole numbers, starting with 1. Which number comes next in the pattern?




Correct answer: (a) 49

  1. 1, 4, 9, 16, 25 and 36 are 1 squared, 2 squared, 3 squared, 4 squared, 5 squared and 6 squared.

  2. 36 is 6 squared, so the next number is 7 squared.

  3. 7 times 7 is 49.

Usual mistake: Continuing a sequence of differences without noticing that the differences are themselves increasing by 2.

Why the other options look tempting

  • (b) Adds 6 to 36, which continues the differences of 3, 5, 7, 9 and 11 but with the wrong step.
  • (c) Adds 12 instead of 13, which is the difference between the last two terms rather than the next one.
  • (d) Gives 6 squared again by adding 9, which is the step two terms back.
Q19OlympiadArithmetic operations

The smallest of three numbers is 3. Each of the other two numbers is 4 more than the one before it. What is the difference between the largest and the smallest of the three numbers?




Correct answer: (c) 8

  1. The three numbers are 3, then 7, then 11, because each step adds 4.

  2. There are two steps from the smallest to the largest.

  3. Two steps of 4 is 2 times 4 = 8.

Usual mistake: Reporting one of the intermediate values rather than the requested difference.

Why the other options look tempting

  • (a) Gives the gap between two neighbouring numbers instead of the gap from the first to the last.
  • (b) Gives the largest number itself, which is 11.
  • (d) Gives the middle number itself, which is 7.
Q20OlympiadNumber puzzles

A two-digit number is written backwards to give another two-digit number. The two numbers add up to 99. If the larger of the two is 68, what is the smaller?




Correct answer: (d) 31

  1. The sum of the two numbers is 99 and the larger one is 68.

  2. The smaller one is 99 − 68.

  3. 99 − 68 is 31, and 68 written backwards is 86, which is not a two-digit reverse of 68, so the pair that matters is 68 and 31.

Usual mistake: Getting tangled in the reversal detail instead of using the sum that is given.

Why the other options look tempting

  • (a) Subtracts 68 from 108 instead of from 99.
  • (b) Subtracts 68 from 97, using the tens digit as if it were part of the sum.
  • (c) Reverses 68 to 86 and then subtracts 45, which is not part of the question.
Q21OlympiadArea and perimeter

A square has a perimeter of 36 cm. What is its area?




Correct answer: (c) 81 square cm

  1. The perimeter of a square is 4 times its side, so the side is 36 divided by 4, which is 9 cm.

  2. The area of a square is the side multiplied by itself, so it is 9 times 9.

  3. 9 times 9 is 81 square cm.

Usual mistake: Confusing perimeter and area, or dividing the perimeter by 2 instead of by 4.

Why the other options look tempting

  • (a) Reports the perimeter again instead of working out the area.
  • (b) Treats half the perimeter, which is 18, as the side instead of dividing the perimeter by 4.
  • (d) Takes the side to be 4, confusing the perimeter with the side length.
Q22OlympiadFractions and decimals

A glass holds exactly 1/3 of a litre. How many such glasses are needed to fill a jug of 4 litres completely?




Correct answer: (a) 12

  1. Each glass holds 1/3 of a litre, so the number of glasses in 4 litres is the number of thirds in 4.

  2. 4 thirds is 3 + 3 + 3 + 3, which is 4 times 3.

  3. So 12 glasses are needed.

Usual mistake: Multiplying by a fraction when the question needs the number of parts, which is a division.

Why the other options look tempting

  • (b) Multiplies 4 litres by 1/3 instead of dividing by 1/3.
  • (c) Uses only the denominator of the fraction and forgets the numerator.
  • (d) Adds the numerator to the denominator before multiplying.
Q23OlympiadNumber patterns

A pattern is made with matchsticks. Step 1 uses 1 matchstick, step 2 uses 2 more, step 3 uses 3 more, step 4 uses 4 more, and so on. How many matchsticks have been used altogether after 5 steps?




Correct answer: (a) 15

  1. Step 1 uses 1, step 2 uses 1 + 2 = 3, step 3 uses 3 + 3 = 6, step 4 uses 6 + 4 = 10.

  2. Step 5 uses 10 + 5 = 15 matchsticks altogether.

  3. After 5 steps the total is 15 matchsticks.

Usual mistake: Stopping one step early, or doubling a total instead of adding to it.

Why the other options look tempting

  • (b) Adds the first four steps only, so the total is one step short.
  • (c) Gives the total after the fourth step, which is 10, not after the fifth.
  • (d) Doubles the total after the fourth step instead of adding the fifth step.
Q24OlympiadGeometry and symmetry

A cube has 6 equal square faces. How many edges does the cube have altogether?




Correct answer: (c) 12

  1. Each of the 6 faces is a square with 4 edges, which counts 24 edges in total across the faces.

  2. But every edge of a cube is shared by exactly 2 faces, so each real edge was counted twice.

  3. So the cube has 24 divided by 2 = 12 edges.

Usual mistake: Counting an edge once for each face it belongs to instead of remembering that two faces share each edge.

Why the other options look tempting

  • (a) Counts 3 edges per face and then halves, but a square face has 4 edges.
  • (b) Reports the number of faces instead of the number of edges.
  • (d) Counts 3 edges per face and forgets to halve, so every edge is counted twice.
Q25OlympiadMoney

A cinema ticket costs Rs.120 for an adult and Rs.60 for a child. A family of 2 adults and 3 children pays with a Rs.1,000 note. How much change are they given?




Correct answer: (b) ₹580

  1. The 2 adult tickets cost 2 times 120, which is Rs.240.

  2. The 3 child tickets cost 3 times 60, which is Rs.180. The total is 240 + 180 = Rs.420.

  3. The change is 1000 − 420 = Rs.580.

Usual mistake: Reporting the cost instead of the change, or using one price for every ticket.

Why the other options look tempting

  • (a) Reports the total cost of the tickets instead of the change that is left.
  • (c) Charges Rs.60 for all 5 tickets, using the child price for everybody.
  • (d) Counts only the 2 adult tickets and forgets the 3 children altogether.
Q26OlympiadWorking backwards

Some marbles are shared equally among 4 children so that each child gets 3 marbles, and then 8 marbles are found to be left over. How many marbles were there to start with?




Correct answer: (b) 20

  1. Work backwards. 8 marbles were left over, so the marbles that were shared out number 20 − 8.

  2. Alternatively, build it forwards: 4 children at 3 marbles each is 4 times 3, which is 12, and the 8 left over must be added.

  3. So there were 12 + 8 = 20 marbles.

Usual mistake: Leaving out the remainder when rebuilding the original amount.

Why the other options look tempting

  • (a) Subtracts the 8 leftover marbles from the total instead of adding them.
  • (c) Counts only the marbles that were shared out and forgets the 8 left over.
  • (d) Multiplies 4 by 8 instead of 4 by 3, using the leftover count in place of the number of marbles per child.
Q27OlympiadMeasurement

A jug holds 2 litres of water. How many cups of 200 millilitres each can be filled completely from the jug?




Correct answer: (d) 10

  1. 2 litres is 2000 millilitres.

  2. Each cup holds 200 millilitres, so the number of full cups is 2000 divided by 200.

  3. 2000 divided by 200 is 10 cups.

Usual mistake: Guessing a different cup size instead of using the size that is given.

Why the other options look tempting

  • (a) Assumes each cup holds 250 millilitres, which was not stated.
  • (b) Assumes each cup holds 150 millilitres, which was not stated.
  • (c) Assumes each cup holds 400 millilitres, which was not stated.
Q28OlympiadMoney

Rita buys 5 apples at Rs.25 each and 3 bananas at Rs.8 each. She pays the shopkeeper with a Rs.200 note. How much does she have to pay in total?




Correct answer: (c) ₹149

  1. The 5 apples cost 5 times 25, which is Rs.125.

  2. The 3 bananas cost 3 times 8, which is Rs.24.

  3. The total is 125 + 24 = Rs.149.

Usual mistake: Answering with the change rather than the amount spent.

Why the other options look tempting

  • (a) Reports the change from Rs.200 instead of the cost of the fruit.
  • (b) Adds up only the apples and forgets the bananas.
  • (d) Adds the number of fruits to the apple cost instead of adding the cost of the bananas.
Q29ChampionNumber puzzles

A two-digit number is 3 times the product of its two digits. What is the largest two-digit number with this property?




Correct answer: (b) 24

  1. Let the tens digit be a and the units digit be b. The number is 10a + b and the product of the digits is a multiplied by b.

  2. So 10a + b = 3ab. Testing the digits from 1 to 9 leaves only two answers: 15, because 3 times 1 times 5 is 15, and 24, because 3 times 2 times 4 is 24.

  3. The largest of the two is 24.

Usual mistake: Assuming a property must survive reversing the digits.

Why the other options look tempting

  • (a) This is the other number that works, but the question asks for the largest.
  • (c) Assumes that if a number works then so does its reverse, but 54 is not 3 times 5 times 4.
  • (d) Adds the digits and multiplies by 3, giving 3 times 9, which is 27 and not 36.
Q30ChampionNumber patterns

A tower is built with square layers. The bottom layer has 1 cube, the layer above it has 4 cubes, then 9 cubes, then 16 cubes. How many cubes are in the sixth layer?




Correct answer: (b) 36

  1. 1, 4, 9 and 16 are the squares of 1, 2, 3 and 4, so layer n holds n multiplied by n cubes.

  2. The fifth layer would hold 5 multiplied by 5, which is 25, and the sixth layer holds 6 multiplied by 6.

  3. 6 multiplied by 6 is 36 cubes.

Usual mistake: Counting the layers back from the end, or adding the layer sizes instead of squaring.

Why the other options look tempting

  • (a) Gives the count for the fifth layer, which is one layer behind the one asked for.
  • (c) Adds the layer sizes together instead of using the square rule, which builds a total rather than one layer.
  • (d) Keeps adding 9, 11 and 13 as equal steps instead of squaring the layer number.
Q31ChampionLogical reasoning

Three boxes are labelled Apples, Mangoes and Mixed, but every label has been put on the wrong box. You are allowed to draw just one fruit from just one box. Which box should you draw from so that you can be certain of working out the contents of all three boxes?




Correct answer: (d) The box labelled Mixed

  1. Because every label is wrong, no box contains what its label says.

  2. So the box labelled Mixed is definitely not mixed. It must hold all apples or all mangoes.

  3. One fruit drawn from that box tells us which it is, and the other two boxes are then fixed by elimination. So the right box to draw from is the box labelled Mixed.

Usual mistake: Choosing a box that is simply not one thing, without checking whether it could be the mixture.

Why the other options look tempting

  • (a) This box is certainly not all apples, but it could be the mixed box, so one fruit from it would not settle the contents.
  • (b) This box is certainly not all mangoes, but it could be the mixed box, so one fruit from it would not settle the contents.
  • (c) Only the box that is guaranteed not to be mixed works, so the choice cannot be left open.
Q32ChampionRemainders

A number leaves remainder 4 when it is divided by 6, and it also leaves remainder 4 when it is divided by 5. What is the smallest such number that is greater than 20?




Correct answer: (b) 34

  1. Subtracting 4 from the number leaves something divisible by both 6 and 5.

  2. A number divisible by both 6 and 5 is a multiple of 30.

  3. So the number is 4 more than a multiple of 30. The values are 4 and 34, and 4 is too small.

  4. So the smallest such number above 20 is 34.

Usual mistake: Finding the first match and stopping without checking that it clears the stated bound.

Why the other options look tempting

  • (a) 29 leaves remainder 5 when divided by 6 rather than remainder 4.
  • (c) 24 leaves remainder 0 when divided by 6 rather than remainder 4.
  • (d) 44 leaves remainder 1 when divided by 5 rather than remainder 4.
Q33ChampionFactors and multiples

How many different factors does the number 36 have? Remember that 1 and 36 are both counted as factors.




Correct answer: (b) 9

  1. 36 can be written as 2 multiplied by 2 multiplied by 3 multiplied by 3, that is 2 squared times 3 squared.

  2. For the prime 2 raised to the power 2 there are 3 choices of power, 1, 2 and 4, and the same for the prime 3 with 1, 3 and 9.

  3. The factors are 1, 2, 3, 4, 6, 9, 12, 18 and 36, and 3 times 3 gives 9.

Usual mistake: Counting multiples instead of factors, or double counting by counting from both ends.

Why the other options look tempting

  • (a) Lists 1, 2, 3, 4, 6 and 9, then forgets that 12, 18 and 36 also divide 36 exactly.
  • (c) Counts each factor twice, once counting up from 1 and once counting down from 36.
  • (d) Counts the multiples of 2 up to 36 rather than the factors of 36.
Q34ChampionCounting

A large triangle is divided into 4 rows of small equal triangles, with 1 in the top row, 2 in the next, 3 in the next and 4 in the bottom row. How many triangles of any size are there in the whole figure, counting both upward and downward triangles?




Correct answer: (a) 27

  1. Upward triangles of side 1 number 1 + 2 + 3 + 4, which is 10, and there are 6, 3, 1 and 0 of side 2, 3 and 4, so 20 upward triangles in all.

  2. Downward triangles number 6 of side 1 and 1 of side 2, so 7 downward triangles.

  3. That gives 20 + 7 = 27 triangles altogether.

Usual mistake: Counting only the triangles that point the same way as the outline.

Why the other options look tempting

  • (b) Counts only the smallest triangles, both the 10 that point up and the 6 that point down.
  • (c) Counts only the triangles that point the same way as the large triangle, leaving out the 7 downward ones.
  • (d) Counts all 20 upward triangles but only 5 of the 7 downward ones.
Q35ChampionTime and speed

A clock shows 3:45 in the afternoon. What is the smaller angle between the hour hand and the minute hand at that moment? Give your answer in degrees.




Correct answer: (d) 157.5 degrees

  1. The minute hand points at the 9, which is 45 times 6, or 270 degrees, round from 12.

  2. By 3:45 the hour hand has moved past 3 by three quarters of an hour, so it is at 3 and three quarters of 30 degrees, which is 112.5 degrees.

  3. The angle between them is 270 − 112.5 = 157.5 degrees, and that is the smaller of the two angles.

Usual mistake: Treating the hour hand as still sitting exactly on the hour mark when the minutes have moved on.

Why the other options look tempting

  • (a) Gives the position of the hour hand alone, which is not the angle between the two hands.
  • (b) Places the hour hand exactly at 3 and the minute hand at 9 and then takes 270 − 90 the wrong way round.
  • (c) Uses the 3 o’clock position for both hands, which is only true at exactly 3 o’clock.

Related practice

Want to work through these topics slowly instead of against the clock? Use the
Class 4 Maths Olympiad
question bank — 50 problems with full worked solutions
. It also explains, for every wrong
option, why a student would be tempted to choose it.

Written and checked by Pandey Sir. Every one of the 35 answers on this page was recomputed by a verification script before it was published, and each wrong option carries a written reason explaining why a student would pick it. Last reviewed: 28 September 2026. Spotted a mistake? Report an error or email [email protected] and we will fix it.
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